蓝线是分子分母同时除以(3+y₀²),然后得到后面的式子
设m=y₀,便于手机书写,请谅解!
y+2m/(m^2+1)=[8m
/6(3-m^2)][X-(3m^2-3)/(m^2+1)]
y=[4m/3(3-m^2)]X-4m(m^2-1)/[(m^2+1)(3-m^2)]-2m/(m^2+1)
=[4m/3(3-m^2)]X-4m(m^2-1)/[(m^2+1)(3-m^2)]-2m(3-m^2)/[(m^2+1)(3-m^2)]
=[4m/3(3-m^2)]X-{4m(m^2-1)-2m(3-m^2)}/[(m^2+1)(3-m^2)]
=[]X+(-4m^3+4m-6m+2m^3)/[(m^2+1)(3-m^2)]
=[]X-(2m^3+2m)/[(m^2+1)(3-m^2)]
=[]X-2m(m^2+1)/[(m^2+1)(3-m^2)]
=[]X-2m/(3-m^2)
=[]X+2m/(m^2-3)
[]中填写X的系数
等式左边是y+2y₀/(y²₀+1),你没有移过来,总能算出答案…
追问我上面书写有步骤,将y₀用m代替,以便手机书写,X的系数是正确的,我用[]代替.
你将那步骤书写一下即可!
你书写y,少减去2y₀/(y²₀+1)
追问黑线是用了,然后代入约分