因式分解数学题 过程 在线等

(1) (5m²+3n²)²-(3m²+5n²)²
(2) xy³-2x²y²+x³y (³ 这个是3)
(3) (x²+4y²)²-16x²y²

第1个回答  2012-04-04
(1)平方差公式 a²- b²=(a+b)·(a-b)
(5m²+3n²)²-(3m²+5n²)²
=(5m²+3n²+3m²+5n²)·(5m²+3n²-3m²-5n²)
=(8m²+8n²)(2m²-2n²)
=16(m²+n²)(m﹢n)(m-n)
(2)xy³-2x²y²+x³y
=xy(y²-2xy+x²)
=xy(y-x)²
(3)(x²+4y²)²-16x²y²
=(x²)²+8x²y²+(4y²)²-16x²y²
= (x²)²-8x²y²+(4y²)²
=(x²-4y²)²
=(x+2y)²(x-2y)²
第2个回答  2012-04-04
(1)原式=2(5m²+3n²-3m²-5n²)
=2(2m²-2n²)
=4m²-4n²
=(2m+2n)(2m-2n)
(2)原式=xy(y²-2xy+x²)=xy(y-x)²
(3)原式=(x^2+4y^2)^2-16x^2y^2
=(x²+4y²)²-(4xy)²
=(x²+4y²+4xy)(x²+4y²-4xy)
=(x+2y)²(x-2y)²
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第3个回答  2012-04-04
(1)(5m^2+3n^2+3m^2+5n^2)(5m^2+3n^2-3m^2-5n^2)
=(8m^2+8n^2)(2m^2-2n^2)
= 16(m^2+n^2)(m+n)(m-n)
(2)先提取一个Xy,得到xy(y^2-2xy+x^2)=xy(x-y)(x-y)
(3)先把括号里展开,得x^4+8x^2y^2+16y^4-16x^2y^2
=x^4-8x^2y^2+16y^4=(x^2-4y^2)^2
第4个回答  2012-04-04
1〉原式=25m^4 9n^4 30m^2n^2-9m^4-25n^4-30m^2n^2
=16m^4-16n^4
=16(m^4-n^4)
=16(m^2 n^2)(m n)(m-n)
2〉
原式=xy(y^2-2xy x^2)
=xy(y-x)^2
3〉
原式=x^4 16y^4 8x^2y^2-16x^2y^2
=x^4 16y^4-8x^2y^2
=(x^2-4y^2)^2
(注:x^4表示x的4次方)
第5个回答  2012-04-04
(1) (5m²+3n²)²-(3m²+5n²)²
=(5m^2+3n^2-3m²-5n²)*(5m²+3n²+3m²+5n²)
=(2m²-2n^2)*(8m²+8n²)
=16(m-n)*(m+n)*(m^2+n^2)
(2) xy³-2x²y²+x³y (³ 这个是3)
=xy*(y^2-2xy+x^2)
=xy*(x-y)^2
(3) (x²+4y²)²-16x²y²
=(x²+4y²-4xy)*(x²+4y²+4xy)
=(x-2y)^2*(x+2y)^2