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¬å¼ f(x)=f(0)+f'(0)x+f''(0)*x²/2!+â¦â¦+o(x^n)
对äºé¢ä¸çf(x), æ fï¼0ï¼=0
f'(x)=(x+1)e^x ---> fâï¼0ï¼=1
f''(x)=(x+2)e^x .... ä¾æ¬¡ç±»æ¨ f''(0)=2
fn(x)=(x+n)e^x --->fn(0)=n
å æ¤éº¦æ°å
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f(x)=x+2x²/2! + 3x³/3! +â¦â¦+n*x^n/n!+o(x^n)
=Σx^n/(n-1)! +o(x^n)
å®æ¯ï¼ä¸æ请追é®ã谢谢
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