r1+r2+r3+...+rn
a+(n-1) a+(n-1) a+(n-1) ... a+(n-1)
1 a 1 ... 1
1 1 a ... 1
... ...
1 1 1 ... a
当 a+(n-1)≠0 时
r1*1/[a+(n-1)]
1 1 1 ... 1
1 a 1 ... 1
1 1 a ... 1
... ...
1 1 1 ... a
ri-r1, i=2,3,...,n
1 1 1 ... 1
0 a-1 0 ... 0
0 0 a-1... 0
... ...
0 0 0 ...a-1
此时, 若a=1,则 r(A) = 1, 否则 r(A) = n.
当 a+(n-1)=0 时, A->
0 0 0 ... 0
1 a 1 ... 1
1 1 a ... 1
... ...
1 1 1 ... a
ri-rn, i=2,3,...,n-1
0 0 0 ... 0
0 a-1 0 ... 0
0 0 a-1... 0
... ...
1 1 1 ... a
此时, 若a=1,则 r(A) = 1, 否则 r(A) = n-1.
满意请采纳^_^.
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