ä¾1å解å å¼ï¼x^15+m^12+m^9+m^6+m^3+1
解åå¼=ï¼x^15+m^12ï¼+(m^9+m^6)+(m^3+1)
=m^12(m^3+1)+m^6(m^3+1)+(m^3+1)
=(m^3+1)(m^12+m^6++1)
=(m^3+1)[(m^6+1)2-m^6]
=(m^+1)(m^2-m^+1)(m^6+1+m^3)(m^6+1-m^3)
ä¾2å解å å¼ï¼x^4+5x^3+15x-9
解æå¯æ ¹æ®ç³»æ°ç¹å¾è¿è¡åç»
解åå¼=ï¼x^4-9ï¼+5x^3+15x
=(x^2+3)(x2-3)+5x(x^2+3)
=(x^2+3)(x^2+5x-3)
1ï¼ä¸åå å¼å解ä¸ï¼æ£ç¡®çæ¯ï¼ ï¼���������
(A) 1- 14 x2= 14 (x + 2) (x- 2) (B)4x â2 x2 â 2 = - 2(x- 1)2
(C) ( x- y )3 â(y- x) = (x â y) (x â y + 1) ( x ây â 1)
(D) x2 ây2 â x + y = ( x + y) (x â y â 1)
2ï¼ä¸ååçå¼(1) a2ï¼ b2 = (a + b) (aâb ),(2) x2â3x +2 = x(xâ3) + 2
(3 ) 1 x2 ây2 ï¼1 ( x + y) (x â y ) ,(4 )x2 + 1 x2 ï¼2ï¼ï¼ x ï¼1x )2
ä»å·¦å°æ¯å å¼å解ç个æ°ä¸ºï¼ ï¼
(A) 1 个 (B) 2 个 (C) 3 个 (D) 4个
3ï¼è¥x2ï¼mxï¼25 æ¯ä¸ä¸ªå®å
¨å¹³æ¹å¼ï¼åmçå¼æ¯ï¼ ï¼
(A) 20 (B) 10 (C) ± 20 (D) ±10
4ï¼è¥x2ï¼mxï¼nè½å解æ( x+2 ) (x â 5)ï¼åm= ,n= ;
5ï¼è¥äºæ¬¡ä¸é¡¹å¼2x2+x+5må¨å®æ°èå´å
è½å å¼å解ï¼åm= ;
6ï¼è¥x2+kxï¼6æä¸ä¸ªå å¼æ¯(xï¼2)ï¼åkçå¼æ¯ ;
7ï¼æä¸åå å¼å å¼å解ï¼
(1)a3ï¼a2ï¼2a (2)4m2ï¼9n2ï¼4m+1
(3)3a2+bcï¼3ac-ab (4)9ï¼x2+2xyï¼y2
8ï¼å¨å®æ°èå´å
å å¼å解ï¼
(1)2x2ï¼3xï¼1 (2)ï¼2x2+5xy+2y2
èç¹è®ç»ï¼
1. å解ä¸åå å¼ï¼
(1).10a(xï¼y)2ï¼5b(yï¼x) (2).an+1ï¼4anï¼4an-1
(3).x3(2xï¼y)ï¼2xï¼y (4).x(6xï¼1)ï¼1
(5).2axï¼10ayï¼5byï¼6x (6).1ï¼a2ï¼abï¼14 b2
*(7).a4ï¼4 (8).(x2ï¼x)(x2ï¼xï¼3)ï¼2
(9).x5yï¼9xy5 (10).ï¼4x2ï¼3xyï¼2y2
(11).4aï¼a5 (12).2x2ï¼4xï¼1
(13).4y2ï¼4yï¼5 (14)3X2ï¼7X+2
解é¢æ导ï¼
1ï¼ä¸åè¿ç®:(1) (aï¼3)2ï¼a2ï¼6aï¼9 (2) xï¼4ï¼(x ï¼2)( x ï¼2)
(3) ax2ï¼a2xyï¼aï¼a(x2ï¼ax) (4) 116 x2ï¼14 xï¼14 ï¼x2ï¼4xï¼4ï¼(xï¼2)2å
¶ä¸æ¯å å¼å解ï¼ä¸è¿ç®æ£ç¡®ç个æ°æ¯ï¼ ï¼
ï¼Aï¼1 ï¼Bï¼2 ï¼Cï¼3 ï¼Dï¼4
2ï¼ä¸è®ºa为ä½å¼ï¼ä»£æ°å¼ï¼a2ï¼4aï¼5å¼ï¼ ï¼
ï¼Aï¼å¤§äºæçäº0 ï¼Bï¼0 ï¼Cï¼å¤§äº0 ï¼Dï¼å°äº0
3ï¼è¥x2ï¼2ï¼mï¼3ï¼xï¼16 æ¯ä¸ä¸ªå®å
¨å¹³æ¹å¼ï¼åmçå¼æ¯ï¼ ï¼
ï¼Aï¼ï¼5 ï¼Bï¼7 ï¼Cï¼ï¼1 ï¼Dï¼7æï¼1
4ï¼(x2ï¼y2)(x2ï¼1ï¼y2)ï¼12ï¼0,åx2ï¼y2çå¼æ¯ ï¼
5ï¼å解ä¸åå å¼ï¼
(1).8xy(xï¼y)ï¼2(yï¼x)3 ï¼(2).x6ï¼y6
(3).x3ï¼2xyï¼xï¼xy2 ï¼(4).(xï¼y)(xï¼yï¼1)ï¼12
(5).4abï¼ï¼1ï¼a2ï¼ï¼1ï¼b2ï¼ (6).ï¼3m2ï¼2mï¼4
ï¼4ãå·²ç¥aï¼bï¼1,æ±a3ï¼3abï¼b3çå¼
5ï¼aãbãc为â¿ABCä¸è¾¹ï¼å©ç¨å å¼å解说æb2ï¼a2ï¼2acï¼c2ç符å·
6ï¼0ï¼aâ¤5ï¼a为æ´æ°ï¼è¥2x2ï¼3xï¼aè½ç¨ååç¸ä¹æ³å解å å¼ï¼æ±ç¬¦åæ¡ä»¶ça
ç¬ç«è®ç»ï¼
1ï¼å¤é¡¹å¼x2ï¼y2, x2ï¼2xyï¼y2, x3ï¼y3çå
¬å å¼æ¯ ã
2ï¼å¡«ä¸éå½çæ°æå¼ï¼ä½¿å·¦è¾¹å¯å解为å³è¾¹çç»æï¼
(1)9x2ï¼( )2ï¼(3xï¼ )( ï¼15 y), (2).5x2ï¼6xyï¼8y2ï¼(x )( ï¼4y).
3ï¼ç©å½¢çé¢ç§¯ä¸º6x2ï¼13xï¼5 (x>0),å
¶ä¸ä¸è¾¹é¿ä¸º2xï¼1,åå¦ä¸º ã
4ï¼æa2ï¼aï¼6å解å å¼ï¼æ£ç¡®çæ¯( )
(A)a(aï¼1)ï¼6 (B)(aï¼2)(aï¼3) (C)(aï¼2)(aï¼3) (D)(aï¼1)(aï¼6)
5ï¼å¤é¡¹å¼a2ï¼4abï¼2b2,a2ï¼4abï¼16b2,a2ï¼aï¼14 ,9a2ï¼12abï¼4b2ä¸ï¼è½ç¨å®å
¨å¹³æ¹å
¬å¼å解å å¼çæ( )
(A) 1个 (B) 2个 (C) 3个 (D) 4个
6ï¼è®¾(xï¼y)(xï¼2ï¼y)ï¼15ï¼0,åxï¼yçå¼æ¯ï¼ ï¼
(A)-5æ3 (B) -3æ5 (C)3 (D)5
7ï¼å
³äºçäºæ¬¡ä¸é¡¹å¼x2ï¼4xï¼cè½å解æ两个æ´ç³»æ°çä¸æ¬¡ç积å¼ï¼é£ä¹cå¯åä¸é¢å个å¼ä¸çï¼ ï¼
(A) ï¼8 (B) ï¼7 (C) ï¼6 (D) ï¼5
8ï¼è¥x2ï¼mxï¼nï¼(xï¼4)(xï¼3) åm,nçå¼ä¸ºï¼ ï¼
(A) mï¼ï¼1, nï¼ï¼12 (B)mï¼ï¼1,nï¼12 (C) mï¼1,nï¼ï¼12 (D) mï¼1,nï¼12.
9ï¼ä»£æ°å¼y2ï¼myï¼254 æ¯ä¸ä¸ªå®å
¨å¹³æ¹å¼ï¼åmçå¼æ¯ ã
10ï¼å·²ç¥2x2ï¼3xyï¼y2ï¼0ï¼x,yåä¸ä¸ºé¶ï¼ï¼å xy ï¼ yx çå¼ä¸º ã
11ï¼å解å å¼:
(1).x2(yï¼z)ï¼81(zï¼y) (2).9m2ï¼6mï¼2nï¼n2
ï¼(3).ab(c2ï¼d2)ï¼cd(a2ï¼b2) (4).a4ï¼3a2ï¼4
ï¼(5).x4ï¼4y4 ï¼(6).a2ï¼2abï¼b2ï¼2aï¼2bï¼1
12ï¼å®æ°èå´å
å å¼å解
ï¼1ï¼x2ï¼2xï¼4 ï¼2ï¼4x2ï¼8xï¼1 ï¼3ï¼2x2ï¼4xyï¼y2
åäºæ°å¦å å¼å解æµè¯é¢
åé¦ç
ä¸ã éæ©é¢ï¼
1. å¤é¡¹å¼15x3y4m2ï¼35x4y2m2+20x3ymçå项å
¬å å¼æ¯ï¼ ï¼
A 5x3y B 5x3ym C 5x3m D5x3m2y
2. ä¸åä»å·¦å°å³çåå½¢ä¸æ¯å å¼å解çæ¯ï¼ ï¼
A (a+b)2=a2+2ab+b2 B x2-4x+5=(x-2x)2+1
C x2-5x-6=(x+6)(x-1) D x2-10x+25=(x-5)2
3. è¥å¤é¡¹å¼x2+kxy+9y2æ¯ä¸ä¸ªå®å
¨å¹³æ¹å¼ï¼åkçå¼ä¸ºï¼ ï¼
A 6 B 3 C ï¼6 D ï¼6æ6
4. æå¤é¡¹å¼a2+a-b2-bç¨åç»å解æ³å解å å¼ä¸åçåç»æ¹æ³æï¼ ï¼
A 1ç§ B 2ç§ C 3ç§ D 4ç§
5. å¤é¡¹å¼a2+b2, x2-y2, -x2-y2, -a2+b2ä¸ï¼è½å解å å¼çæï¼ ï¼
A 4个 B 3个 C 2个 D 1个
6. å¦æå¤é¡¹å¼x2ï¼mxï¼15è½å解å å¼ï¼åmçå¼ä¸ºï¼ ï¼
A 2æï¼2 B 14æï¼14 C 2æï¼14 D ±2æ±14
7. ä¸ååå¤é¡¹å¼ä¸ä¸å«æå å¼ (x-1) çæ¯ï¼ ï¼
A x3-x2-x+1 B x2+y-xy-x C x2-2x-y2+1 D (x2+3x)2-(2x+2)2
8. è¥ åxä¸ºï¼ ï¼
A 1 B ï¼1 C D ï¼2
9. è¥å¤é¡¹å¼4abï¼4a2ï¼b2ï¼mæä¸ä¸ªå å¼ä¸ºï¼1-2a+bï¼åmçå¼ä¸ºï¼ ï¼
A 0 B 1 C ï¼1 D 4
10. å¦æ (a2ï¼b2ï¼3) (a2+b2) ï¼10 = 0é£ä¹a2+b2çå¼ä¸ºï¼ ï¼
A ï¼2 B 5 C 2 D ï¼2æ5
äºãå解ä¸ååå¼ï¼
1ã- m2 â n2 + 2mn + 1 2ã(a + b)3d â 4(a + b)2cd+4(a + b)c2d
3. (x + a)2 â (x â a)2 4.
5. âx5y â xy +2x3y 6. x6 â x4 â x2 + 1
7. (x +3) (x +2) +x2 â 9 8. (x ây)3 +9(x â y) â6(x â y)2
9. (a2 + b2 â1 )2 â 4a2b2 10. (ax + by)2 + (bx â ay)2
ä¸ã ç®ä¾¿æ¹æ³è®¡ç®ï¼
1. 2.
åã åç®æ±å¼ï¼
1. 2ax2 â 8axy + 8ay2 â 2a 2. å·²ç¥ï¼a2 â b2 â 5=0 c2 â d2 â 2 =0
å
¶ä¸x â2 y =1 a=3 æ±ï¼(ac + bd)2 â (ad + bc)2çå¼
äºã è§å¯ä¸åå解å å¼çè¿ç¨ï¼ å解å å¼çæ¹æ³ï¼å«å é
æ¹æ³ã
x2 + 2ax â 3a2 è¯·ä½ ç¨é
æ¹æ³å解å å¼ï¼
=x2+2ax+a2 â a2 â 3a2 ï¼å
å ä¸a2,ååå»a2ï¼ m2 â 4mn +3n2
=(x+a)2 â 4a2 ï¼è¿ç¨å®å
¨å¹³æ¹å
¬å¼ï¼
=(x+a+2a) (x+a â 2a) ï¼è¿ç¨å¹³æ¹å·®å
¬å¼ï¼
=(x+3a) (x â a)
åä¸é¢è¿æ ·éè¿å å项é
åºå®å
¨å¹³æ¹å¼æäºæ¬¡ä¸é¡¹å¼
温馨提示:答案为网友推荐,仅供参考