（x＋y－2xy）（x＋y－2）＋（xy－1）²因式分解

如题所述

举报该问题

第1个回答 2014-12-04

（x＋y－2xy）（x＋y－2）＋（xy－1）²
=（x+y)²-(2xy+2)(x+y)+4xy+x²y²-2xy+1
=（x+y)²-2(xy+1)(x+y)+(x²y²+2xy+1)
=（x+y)²-2(xy+1)(x+y)+(xy+1)²
=[(x+y)-(xy+1)]²
=(x+y-xy-1)²追问

％#178是不用看嘛？

追答

电脑网速有问题吧，％#178这些应该是平方

追问

3Q～

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