暑假作业因式分解(x+y-2xy)(x+y)+(xy-1)2

Question

急，各位帮帮忙，最后的2是（xy-1)的平方的意识
题目修改一下，变成(x+y-2xy)(x+y-2)+(xy-1)2

Answer 1

x的平方+2xy+y的平方-2(x的平方）y-2x（y的平方）-x的平方y的平方+2xy-1

Answer 2

x+y-2XY)(x+y-2)+(xy-1)^2
=[（x+y)-2xy][(x+y)-2]+(xy-1)^2
=(x+y)^2-2(xy+1)(x+y)+4xy+x^2y^2-2xy+1
=(x+y)^2-2(xy+1)(x+y)+x^2y^2+2xy+1
=(x+y)^2-2(xy+1)(x+y)+(xy+1)^2
=[(x+y)-(xy+1)]^2
=(x+y-xy-1)^2
=[x(1-y)-(1-y)]^2
=(x-1)^2(1-y)^2
=(x-1)^2(y-1)^2本回答被提问者采纳

Answer 3

(x+y)(x+y)-2xy(x+y)+(x-y)(x-y)