初一数学题(x²-y)²-（2y-2）²因式分解

Question

如题所述

Answer 1

(x²-y)²-（2y-2)²
=(x²-y+2y-2)(x²-y-2y+2)
=(x²+y-2)(x²-3y+2)
运用平方差公式

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Answer 2

(x²-y)²-（2y-2）²
=[(x²-y)+（2y-2）][(x²-y)-（2y-2）]
=(x²-y+2y-2)(x²-y-2y+2)
=(x²+y-2)(x²-3y+2)

Answer 3

解；原式=（x^4-2x²y+y²）-（4y²-8y+4）
=x^4-2x²y+y²-4y²+8y-4
=x^4-2x²y-3y²+8y-4。