初一因式分解x^4-8x^2y^2+16y^4

Question

如题所述

Answer 1

解：原式=(x^2)^2-8x^2y^2+(4y^2）^2
=(x^2-4y^2)^2
=(X+2Y)^2 (x-2y)^2

Answer 2

x^4-8x^2y^2+16y^4
=(x^2-4y^2)^2
=[(x-2y)(x+2y)]^2
=(x-2y)^2*(x+2y)^2

Answer 3

x^4-8x^2y^2+16y^4=(x^2-4y^2)^2
这是一个完全平方式啊

Answer 4

(X^2-4Y^2)^2

Answer 5

原式=（x²）²-2×4y²×x²+(4y²)²
=（x²-4y²）²
=[(x-2y)(x+2y)]²本回答被提问者采纳