第2个回答 2017-02-21
e^y=e^x=sin(xy)
则,(e^y)'-(e^x)'=[sin(xy)]'
==> (e^y)*y'-(e^x)*x'=cos(xy)*(xy)'
==> (e^y)*y'-(e^x)=cos(xy)*(x'*y+x*y')
==> (e^y)*y'-(e^x)=cos(xy)*(y+xy')
==> (e^y)*y'-x*cos(xy)*y'=ycos(xy)+e^x
==> y'=[ycos(xy)+e^x]/[e^y-xcos(xy)]
y'的意思就是dy/dx,不是dy!!本回答被提问者采纳