åå§æ¶å»çæçµè·¯
æ±è§£å¨æçµè·¯çååºæ¶ï¼éè¦ç¥éååºçåå§å¼y(0)ã设çµè·¯å¨t=0æ¶å»æ¢è·¯ï¼ç§°æ¢è·¯åçç¬é´ä¸ºt=0-ï¼æ¢è·¯åçç¬é´ä¸ºt=0+ãæ们è¦æ±çæ¯y(0+)ãä¸è¬åéy(0+)åå³äºçµè·¯å¨t=0+æ¶å»çµè·¯çç¶æ ï¼uc(0+)åil(0+)ï¼åå¤å æ¿å±å¨t=0+æ¶å»çåå¼ãå¨æéåççæ
åµä¸ï¼ç¶æéä¸è½çªåï¼å³
uc(0+)=uc(0-)
il(0+)=il(0-)
å
·æåå§çµåuc(0+)çå¨t=0+æ¶å»ç¸å½äºä¸ä¸ªçµåæºï¼å
·æåå§çµæµil(0+)ççµæå¨t=0+æ¶å»ç¸å½äºä¸ä¸ªçµæµæºãæå®ä»¬åå«ç¨çµåæºåçµæµæºä»£æ¿ï¼å¯ä»¥å¾å°t=0+åå§æ¶å»çæçµè·¯ï¼å¦ä¸å¾ï¼ï¼ç¨æ¥è®¡ç®ä»»æåéçåå§å¼ã



ä¾1å³å¾æ示çµè·¯å¨t=0æ¶æ¢è·¯ï¼çµå®¹ä¸åæ¥æçµåuc(0-)=4v,æ±çµå®¹çµååçµæµå¨t=0+æ¶åå§å¼ã
解 å¨t=0+æ¶ï¼å¼å
³éåï¼ç±çµå®¹çæ¢è·¯ç¹æ§ï¼uc(0+)=uc(0-)=4v,å°çµå®¹ç¨4vçµåæºä»£æ¿ååºt=0+æ¶å»çæçµè·¯å¦å¾ï¼ç±æ¤è®¡ç®åº
i(0+)=(12-4)/1=8aç´æµç¨³æçæçµè·¯
对äºç¨³å®çµè·¯ï¼å¨ç»è¿è¶³å¤é¿çæ¶é´åï¼å³ç论ä¸tââæ¶ï¼çµè·¯ææååºæ¶å¤±ï¼åªå©ä¸ä¸å¤å æ¿å±æå
³çåéãå¨ç´æµæ¿å±ä¸ï¼çµè·¯ä¸åé¨åçµååçµæµä¸åååï¼ä¸ºä¸ä¸ªå¸¸éï¼ç¨³æå¼ï¼ï¼æ¤æ¶

å³ï¼çµå®¹ç¸å½äºå¼è·¯ï¼çµæç¸å½äºçè·¯ã以æ¤ä¸ºä¾æ®ï¼å¯ååºç´æµæ¿å±ä¸t=âçæçµè·¯ï¼ç´æµç¨³æçæçµè·¯ï¼ï¼ ç¨æ¥è®¡ç®åéçç´æµç¨³æå¼y(â)ãç´æµç¨³æå¼y(â)ç计ç®å¨æ±åéçåå§å¼ï¼ç¨ä¸è¦ç´ æ³åæä¸é¶çµè·¯æ¶é½è¦ç¨å°ã

å¨ä¾1æ示çµè·¯ä¸ï¼è¥æ±t=âæ¶åéç稳æå¼ï¼ååºt=âçæçµè·¯ï¼æ±åº
uc(â)=12v, i(â)=0ãåå§å¼å稳æå¼è®¡ç®å®ä¾
ä¾1 æ±u(0+)=?

解ï¼åå®å¼å
³æå¼åçµè·¯å·²ç»å¤äºç¨³æï¼è®¡ç®çµå®¹çµå

t=0+,2Ïæ¯è·¯å¼è·¯ï¼c代ä¹ä»¥4vççµåæºï¼å¾å°t=0+çæ(b)
ä¾1 æ±il(â)=?

解ï¼tââï¼ å°3hçµæ代ä¹ä»¥çè·¯ï¼å¾å°å¾(b)稳æçæçµè·¯

温馨提示:答案为网友推荐,仅供参考