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    • ∫cos2xcos3xdx 求解

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    推荐答案   2014-07-13
    cos2xcos3x =cos3xcos2x =(1/2){cos(3x+2x)+cos(3x-2x)} =(1/2)(cos5x+cosx) ∫ cos2xcos3 xdx =(1/2)∫(cos5x+cosx)dx =(1/2){(1/5)sin5x+sinx}+C =(1/10)sin5x+(1/2)sinx+C

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