第1个回答 2021-05-10
y
= ln(3x^2+8)^7/tan(6x)
=7ln(3x^2+8)/tan(6x)
dy/dx
=7[ tan6x.(ln(3x^2+8))' -(ln(3x^2+8)).(tan6x)' ] /[tan(6x)]^2
=7{ [ tan6x.[6x/(3x^2+8)] -(ln(3x^2+8)).[6(sec6x)^2] } /[tan(6x)]^2
=7[ 6x.tan6x -6(ln(3x^2+8)).(sec6x)^2.(3x^2+8) ] /{ [tan(6x)]^2. (3x^2+8) }本回答被提问者采纳