5.解ï¼âµ(x^2+y^2+2x)dx+2ydy=0
==>(x^2+2x)dx+y^2dx+2ydy=0
==>(x^2+2x)e^xdx+y^2e^xdx+2ye^xdy=0 (çå¼ä¸¤ç«¯åä¹e^x)
==>(x^2+2x)e^xdx+d(y^2*e^x)=0
==>â«(x^2+2x)e^xdx+â«d(y^2*e^x)=0
==>x^2*e^x+y^2*e^x=C (Cæ¯ç§¯å常æ°)
==>x^2+y^2=Ce^(-x)
â´æ¤æ¹ç¨çé解æ¯x^2+y^2=Ce^(-x)ã
6.解ï¼âµxy'+y=x^3*y^6
==>(xy)'=(xy)^6/x^3
==>d(xy)/(xy)^6=dx/x^3
==>-(-1/5)/(xy)^5=-(1/2)/x^2+C/10 (Cæ¯ç§¯å常æ°)
==>5x^3*y^5-2=Cx^5*y^5
â´æ¤æ¹ç¨çé解æ¯5x^3*y^5-2=Cx^5*y^5ã
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