å å¼å解(x+2)(x-3)+(x+2)(x+4)= ã
41.å å¼å解2ax2-3x+2ax-3= ã
42.å å¼å解9x2-66x+121= ã
43.å å¼å解8-2x2= ã
44.å å¼å解x2-x+14 = ã
45.å å¼å解9x2-30x+25= ã
46.å å¼å解-20x2+9x+20= ã
47.å å¼å解12x2-29x+15= ã
48.å å¼å解36x2+39x+9= ã
49.å å¼å解21x2-31x-22= ã
50.å å¼å解9x4-35x2-4= ã
51.å å¼å解(2x+1)(x+1)+(2x+1)(x-3)= ã
52.å å¼å解2ax2-3x+2ax-3= ã
53.å å¼å解x(y+2)-x-y-1= ã
54.å å¼å解(x2-3x)+(x-3)2= ã
55.å å¼å解9x2-66x+121= ã
56.å å¼å解8-2x2= ã
57.å å¼å解x4-1= ã
58.å å¼å解x2+4x-xy-2y+4= ã
59.å å¼å解4x2-12x+5= ã
60.å å¼å解21x2-31x-22= ã
61.å å¼å解4x2+4xy+y2-4x-2y-3= ã
62.å å¼å解9x5-35x3-4x= ã
63.å å¼å解ä¸ååå¼:
(1)3x2-6x= ã
(2)49x2-25= ã
(3)6x2-13x+5= ã
(4)x2+2-3x= ã
(5)12x2-23x-24= ã
(6)(x+6)(x-6)-(x-6)= ã
(7)3(x+2)(x-5)-(x+2)(x-3)= ã
(8)9x2+42x+49= ã
(1)(x+2)-2(x+2)2= ã
(2)36x2+39x+9= ã
(3)2x2+ax-6x-3a= ã
(4)22x2-31x-21= ã
70.å å¼å解3ax2-6ax= ã
71.å å¼å解(x+1)x-5x= ã
72.å å¼å解(2x+1)(x-3)-(2x+1)(x-5)=
73.å å¼å解xy+2x-5y-10=
74.å å¼å解x2y2-x2-y2-6xy+4=
x3+2x2+2x+1
a2b2-a2-b2+1
(1)3ax2-2x+3ax-2
(x2-3x)+(x-3)2+2x-6
1)(2x+3)(x-2)+(x+1)(2x+3)
9x2-66x+121
17.å å¼å解
(1)8x2-18 (2)x2-(a-b)x-ab
18.å å¼å解ä¸ååå¼
(1)9x4+35x2-4 (2)x2-y2-2yz-z2
(3)a(b2-c2)-c(a2-b2)
19.å å¼å解(2x+1)(x+1)+(2x+1)(x-3)
20.å å¼å解39x2-38x+8
21.å©ç¨å å¼å解æ±(6512 )2-(3412 )2ä¹å¼
22.å å¼å解a(b2-c2)-c(a2-b2)
24.å å¼å解7(x-1)2+4(x-1)(y+2)-20(y+2)2
25.å å¼å解xy2-2xy-3x-y2-2y-1
26.å å¼å解4x2-6ax+18a2
27.å å¼å解20a3bc-9a2b2c-20ab3c
28.å å¼å解2ax2-5x+2ax-5
29.å å¼å解4x3+4x2-25x-25
30.å å¼å解(1-xy)2-(y-x)2
31.å å¼å解
(1)mx2-m2-x+1 (2)a2-2ab+b2-1
32.å å¼å解ä¸ååå¼
(1)5x2-45 (2)81x3-9x (3)x2-y2-5x-5y (4)x2-y2+2yz-z2
33.å å¼å解:xy2-2xy-3x-y2-2y-1
34.å å¼å解y2(x-y)+z2(y-x)
1)å å¼å解x2+x+y2-y-2xy=
35.å å¼å解x2-25= ã
36.å å¼å解x2-20x+100= ã
37.å å¼å解x2+4x+3= ã
38.å å¼å解4x2-12x+5= ã
39.å å¼å解ä¸ååå¼:
(1)3ax2-6ax= ã
(2)x(x+2)-x= ã
(3)x2-4x-ax+4a= ã
(4)25x2-49= ã
(5)36x2-60x+25= ã
(6)4x2+12x+9= ã
(7)x2-9x+18= ã
(8)2x2-5x-3= ã
(9)12x2-50x+8= ã
(1) çæ¡:a(b−1)(ab+2b+a)
说æ:(ab+b)2−(a+b)2 = (ab+b+a+b)(ab+b−a−b) = (ab+2b+a)(ab−a) = a(b−1)(ab+2b+a).
(2) çæ¡:(x−a)4
说æ:(a2−x2)2−4ax(x−a)2
= [(a+x)(a−x)]2−4ax(x−a)2
= (a+x)2(a−x)2−4ax(x−a)2
= (x−a)2[(a+x)2−4ax]
= (x−a)2(a2+2ax+x2−4ax)
= (x−a)2(x−a)2 = (x−a)4.
(3) çæ¡:7xn−1(x−1)2
说æ:åå¼ = 7xn−1 •x2−7xn−1 •2x+7xn−1 = 7xn−1(x2−2x+1) = 7xn−1(x−1)2.
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