[ {
"id" : "1",
"name" : "一",
"age" : 40,
"children" : [ {
"id" : "1-1",
"name" : "test1",
"age" : 20,
"children" : [ {
"id" : "1-1-1",
"name" : "test1-1",
"age" : 10
}, {
"id" : "1-1-2",
"name" : "test1-2",
"age" : 10
} ]
}, {
"id" : "1-2",
"name" : "test2",
"age" : 20,
"children" : [ {
"id" : "1-2-1",
"name" : "test2-1",
"age" : 10
}, {
"id" : "1-2-2",
"name" : "test2-1",
"age" : 10
} ]
} ]
}, {
"id" : "2",
"name" : "二",
"age" : 10,
"children" : [ {
"id" : "2-1",
"name" : "test1",
"age" : 10,
"children" : [ {
"id" : "2-1-1",
"name" : "test1-1",
"age" : 10
} ]
} ]
} ]
// 删除以上数组中,节点id为1-1-2和1-2-1的节点结果如下
[ {
"id" : "1",
"name" : "一",
"age" : 40,
"children" : [ {
"id" : "1-1",
"name" : "test1",
"age" : 20,
"children" : [ {
"id" : "1-1-1",
"name" : "test1-1",
"age" : 10
}]
}, {
"id" : "1-2",
"name" : "test2",
"age" : 20,
"children" : [ {
"id" : "1-2-2",
"name" : "test2-1",
"age" : 10
} ]
} ]
}, {
"id" : "2",
"name" : "二",
"age" : 10,
"children" : [ {
"id" : "2-1",
"name" : "test1",
"age" : 10,
"children" : [ {
"id" : "2-1-1",
"name" : "test1-1",
"age" : 10
} ]
} ]
} ]
谢谢哈,test里面可能没有1-2-1,此时会报错,加判断应该在哪加,还有如果是这种简单的[{"id":"1-1-1","name":"test1-1","age":10},{"id":"1-1-2","name":"test1-2","age":10}],删除id为1-1-2的得到[{"id":"1-1-1","name":"test1-1","age":10}]该怎么删
追答抱歉没有及时看到...