若a、b互为相反数,cd互为倒数,求（图片）的值

Question

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Answer 1

a、b互为相反数,a+b=0,a=-b;
cd互为倒数,cd=1
³√(a³+b³)+³√(cd)
=³√[(-b)³+b³]+³√(1)
=³√[-b³+b³]+1
=³√[0]+1
=0+1
=1

Answer 2

a+b=0 cd=1
a^3+b^3 = (a+b) (a^2-ab+b^2）=0
等于1