1)éæå·¥ä½ç¹
Vb=[20/(40+20)]12=4V
Ve=4-0.7=3.3V
IcâIe=3.3/3.3=1mA
Ib=Ic/β=0.02mA
V=12-Ic(Rc+Reï¼=12-6.3=5.7V
2)å¨æåæ°
rbe=300+26mV/Ib=300+1300=1600Ω=1.6K
Ri=Rb1//Rb2//rbe=1.43K
Ro=Rc=3K
Av=Uo/Ui=-βRc/rbe=-50x3K/1.6K=-93.75
Avs=Uo/Us=AvRi/(Rs+Ri)=-93.75x1.43/1.93=-69.5追é®
Vb=[20/(40+20)]12=4V
Ve=4-0.7=3.3V
IcâIe=3.3/3.3=1mA
Ib=Ic/β=0.02mA
V=12-Ic(Rc+Reï¼=12-6.3=5.7V
2)å¨æåæ°
rbe=300+26mV/Ib=300+1300=1600Ω=1.6K
Ri=Rb1//Rb2//rbe=1.43K
Ro=Rc=3K
Av=Uo/Ui=-βRc/rbe=-50x3K/1.6K=-93.75
Avs=Uo/Us=AvRi/(Rs+Ri)=-93.75x1.43/1.93=-69.5追é®
Rbe=Rbb+26mv/Ibæ¯ä»ä¹ææ 26mvæ¯ä»ä¹
追çè¿æ¯rbeæ±åå ¬å¼ï¼300Ωå26mVé½æ¯è¯¥å ¬å¼ä¸ç常æ°ã
追é®å¦å¦ï¼é£ä¸ªAuæ¯æä¹ç®ç
追çå°±æ¯å¥å ¬å¼ï¼Av=Uo/Ui=-βRc/rbe
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第1个回答 2015-08-09
算题啊😱
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