第1个回答 2013-04-22
#include<stdio.h>
void main()
{
int m,n=0,count=0;aver=0;
int qq[10];
printf(“input 10 no:”);
for(m=0;m<10;m++)
{
scanf("%d",&qq[m]);
if (qq[m]%2!=0)
{n++;
}
count+=qq[m];
}
aver = count/10;
printf("ji shu you %d ge\n",n);
printf("pingjun shi %d",aver);
getch();
}本回答被网友采纳