第1个回答 2013-06-21
#include <stdio.h>
int max(int a, int b, int c)
{
int m = a;
m = b > c ? b : c;
return m;
}
int min(int a, int b, int c)
{
int m = a;
m = b < c ? b : c;
return m;
}
int main()
{
int a = 3, b = 2, c = 4;
printf("%d\n", max(a,b,c));
printf("%d\n", min(a,b,c));
return 0;
}
第2个回答 2013-06-21
#include<stdio.h>
#include<stdlib.h>
main()
{
int a,b,c,max,min;
scanf("%d%d%d",&a,&b,&c);
max=min=a;
if(b>max)
max=b;
if(c>max)
max=c;
if(b<min)
min=b;
if(c<min)
min=c;
printf("The max is%d\nThe min is%d\n",max,min);
system("pause");
}本回答被网友采纳
第3个回答 2013-06-21
#inculde "stdio.h"void main(){ int a,b,c,max,min;
printf("input a,b,c:");
scanf("%d %d %d",&a,&b,&c);
max=(a>b)?a:b;
max=(max>c)?max:c;
min=(a<b)? a:b;
min=(min<c)? min:c;
printf("max:%d\nmin:%d\n",max,min);}