c语言从键盘输入若干个个整数,求其中奇数之和,偶数之和以及能被 3整除的数之和.

Question

如题所述

Answer 1

#include<stdio.h>
main()
{
int i,x,n,s1=0,s2=0,s3=0;
scanf("%d",&n);
for(i=0;i<n;i++)
{
scanf("%d",&x);
if(x%2)s1+=x;
else s2+=x;
if(x%3==0)s3+=x;
}
printf("奇数之和s1=%d\n",s1);
printf("偶数之和s2=%d\n",s2);
printf("能被3整除的数之和s3=%d\n",s3);
}


Answer 2

有些语法忘记了。
#include <stdio.h>
main()
{
int[10] a;
int sun_jishu = 0;
int sun_oushu = 0;
int sun_3 = 0;
printf("请输入若干整数:\n");
scanf(&a[1], &a[2],........);
for(int i =0; i < 10; i++)
{
if (a[i] %2 == 0)
{
sun_oushu += a[i];
}
else if(a[i] %2 == 0)
{
sun_jishu += a[i];
}
else if (a[i] %3 == 0)
{
sun_3 += a[i];
}
}
prinft("%d,%d,%d",sun_jishu,sun_oushu,sun_3);

}