已知函数y=f(x)=2sin(2x+π/3)+3,x∈[-π/6,π/2]求f（x）的最值以及求得最值时x的值

Question

如题所述

Answer 1

因为x∈[-π/6,π/2]
所以，2x+π/3∈[0,4π/3]
当x=π/2时，f(x)取最小值，f(x)min=-√3+3
当x=π/12时，f(x)取最大值，f(x)max=5