方法一:通过数学方法判断分数是否是无限循环小数,需要确定分子分母是否互质,另外还要判断小数从第几位开始无限循环,比较麻烦。
方法二:直接讲分数运算结果转换成字符串,然后写函数进行字符串比较。代码如下:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/7aec54e736d12f2e17da5dc041c2d562843568b7?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
#include<stdio.h>
#include<string.h>
int checkAnswer(char solution[],char answer[]);//检查回答是否与答案匹配,是返回1,否返回0
int main()
{
char solution[20];//存储1/3的答案字符串
char answer[20];//存储用户输入的回答
sprintf(solution,"%.16lf",1.0/3);//把除法运算结果转化成字符串保存,作为答案
while(1)
{
printf("-----------------\n输入1/3的答案:");
scanf("%s",answer);
if(checkAnswer(solution,answer))
printf("回答正确!\n");
else
printf("回答错误!\n");
printf("-----------------\n");
}
return 0;
}
int checkAnswer(char solution[],char answer[])//检查回答是否与答案匹配,是返回1,否返回0
{
int i,len1=strlen(solution),len2=strlen(answer),len;
if(len2>len1)
len=len1;
else
len=len2;
for(i=0;i<len;i++)
if(solution[i]!=answer[i])
return 0;
return 1;
}