求一维数组a中的值为奇数的元素之和

Question

#include <conio.h>
#include <stdio.h>
int sum( int b[ ],int n )
{ int i,s = 0;
for ( i=0; i<n; i++)
if (b[i] % 2 == 1)
/************found************/
s = s + b[i]
return (s);
}
void main()
{ int a[12]={10,4,2,7,3,12,5,34,5,9,21,19},n;
/************found************/
n = sum(a,2);
printf("The result is :%d\n",n );
}

改错题，找了很久找不到答案，明天就考试了，很急，求大神帮助

Answer 1

#include <stdio.h> 

int sum( int b[ ],int n ) 

{ int i,s = 0; 

for ( i=0; i<n; i++) 

if (b[i] % 2 == 1) 

/************found************/ 

s = s + b[i]  ;

return (s); 

} 

void main() 

{ int a[12]={10,4,2,7,3,12,5,34,5,9,21,19},n; 

/************found************/ 

n = sum(a,12); 

printf("The result is :%d\n",n ); 

}

Answer 2

s=s+b[i];//添加;
n=sum(a,12);//数组大小追问

为什么还是s=s+b[i];？这不没有修改吗

追答

原来少了;

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