某单位申请到一个B类IP地址,其网络标识(NET-ID)为130.53,现进行子网划分,罗选子网

Question

如题所述

Answer 1

网络位+子网位+主机位=32位二进制IP地址。130.53.0.0是点分十进制。根据需求，看贵单位需要多少个子网，然后各子网有多少主机。由实际情况得知：子网位（M）+主机位（N）=16位。子网数量为2的M次方，主机数量为2的N次方减去2.比如需要划分10个子网，每个子网的主机有200个主机。考虑留点余量。可以如下规划：
130.53.0.0/24 = 130.53.0.0 255.255.255.0 = 130.53.0.1----130.53.0.254
130.53.1.0/24 = 130.53.10 255.255.255.0 = 130.53.1.1----130.53.0.254
130.53.2.0/24 = 130.53.2.0 255.255.255.0 = 130.53.2.1----130.53.0.254
130.53.3.0/24 = 130.53.3.0 255.255.255.0 = 130.53.3.1----130.53.0.254
130.53.4.0/24 = 130.53.4.0 255.255.255.0 = 130.53.4.1----130.53.0.254
130.53.5.0/24 = 130.53.5.0 255.255.255.0 = 130.53.5.1----130.53.0.254
130.53.6.0/24 = 130.53.6.0 255.255.255.0 = 130.53.6.1----130.53.0.254
130.53.7.0/24 = 130.53.7.0 255.255.255.0 = 130.53.7.1----130.53.0.254
130.53.8.0/24 = 130.53.8.0 255.255.255.0 = 130.53.8.1----130.53.0.254
130.53.9.0/24 = 130.53.9.0 255.255.255.0 = 130.53.9.1----130.53.0.254
130.53.10.0-----130.53.255.254 作为以后扩展用。