第1个回答 2011-07-12
COUNT((C-MA(C,25))/MA(C,25)*100>0,10)>=10 AND ABS(C-MA(C,25))/MA(C,25)<0.01;
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第2个回答 推荐于2020-12-20
选股:cross(c,ma(c,20)) and count(v<ref(v,1),3)=3;本回答被提问者采纳
第3个回答 2011-07-19
COUNT((C-MA(C,25))/MA(C,25)*100>0,10)>=10 AND ABS(C-MA(C,25))/MA(C,25)<0.01;
第4个回答 2011-07-12
COUNT((C-MA(C,25))/MA(C,25)*100>0,10)>=10 AND ABS(C-MA(C,25))/MA(C,25)<0.01;