分解因式（x+2)(x+4)+x的平方-4

Question

如题所述

Answer 1

解：（x+2)(x+4)+x的平方-4
=x^2+6x+8+x^2-4
=2x^2+6x+4
=(x+1)(2x+4)
祝你进步

Answer 2

原式=x^2+6x+8+x^2-4
=2x^2+6x+4
=2(x^2+3x+2)
=2(x+2)(x+1)

Answer 3

(x+2)(x+4)+x2-4
=(x+2)(x+4)+(x+2)(x-2)
=(x+2)(x+4+x-2)
=2(x+2)(x+1)

Answer 4

原式=(x+2)(x+4)+(x+2)(x-2)=(x+2)(x+4+x-2)=(x+2)(2x+2)

Answer 5

(x+2)(x+4)+x²-4
=(x+2)(x+4)+(x-2)(x+2)
=(x+2)(x+4+x-2)
=(x+2)(2x+2)
=2(x+1)(x+2)本回答被提问者采纳