ⅹ平方-3ⅹ=(2-ⅹ)(ⅹ-3)等于多少？谢谢！

Question

如题所述

Answer 1

x^2-3x=（2-x）（x-3）
x^2-3x=2x-6-x^2+3x
x^2 +x^2-3x-2x-3x+6=0
2x^2-8x+6=0
x^2-4x+3=0
（x-1）（x-3）=0
得
x-1=0
x-3=0

得x=1或者x=3

Answer 2

x²-3x=(2-x)(x-3)
==> x(x-3)=(2-x)(x-3)
==> x(x-3)-(2-x)(x-3)=0
==> (x-3)[x-(2-x)]=0
==> (x-3)(2x-2)=0
==> x-3=0，或2x-2=0
所以，x=3，或者x=1

Answer 3

原式整理得0=x（x-3）-（2-x）（x-3）
=（x-3）（x-2+x）
解得X1=3，X2=1

Answer 4

ⅹ² - 3ⅹ = (2 - ⅹ)(ⅹ - 3)
x² - 3x = - x² + 5x - 6
x² - 4x + 3 = 0
(x - 1)(x - 3) = 0
x = 1 或 x = 3