(1x2x3+3x6x9+7x14x21 )/(1x3x5+3x9x15+7x21x35) =3(1Ã2+6Ã9+7Ã14Ã7ï¼/3ï¼1Ã5+9Ã15+7Ã7Ã35ï¼ =(1Ã2+6Ã9+7Ã14Ã7ï¼/(1Ã5+9Ã15+7Ã7Ã35ï¼ =14(4+7Ã7)/5(1+3Ã9+7Ã7Ã7ï¼ =14Ã53/5Ã7(4+7Ã7) =14Ã53/35Ã53 =14/35 =2/5 å¦æ满æãè¯·å¥½è¯ è°¢è°¢ã
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