某10KV用户负荷为200KW，功率因数0.9，线路电阻2Ω,则线路损耗为多少？

Question

求详细计算过程！！

Answer 1

线电流 I = 200/（√3 * 10 * 0.9 ) = 12.83 A
线路损耗 P = 3 * 2 *12。83^2 = 987.7 W

Answer 2

线电流 I = 200/（√3 * 10 * 0.9 ) = 12.83 A
线路损耗 P = 3 * 2 *12。83^2 = 987.7 W

Answer 3

987.654319W