初二数学：因式分解

Question

因式分解x^2y^2-x^2-y^2+1

Answer 1

解：原式<=>x^2(y^2-1)-(y^2-1) {提出公因式x^2}
=(y^2-1)(x^2-1) {提出公因式y^2-1}
=(y+1)(y-1)(x+1)(x-1) {平方差}

Answer 2

(y-1)(y+1)(x+1)(x-1)

Answer 3

原式=x^2(y^2-1)-(y^2-1)=(y^2-1)(x^2-1)=(x+1)(x-1)(y+1)(y-1)

Answer 4

(x^2-1)(y^2-1)=(x+1)(x-1)(y+1)(x-1)

Answer 5

y-1)(y+1)(x+1)(x-1)

Answer 6

这题并不难啊,答案为(y-1)(y+1)(x+1)(x-1)