如题所述
å æç §é¢æä½å¾å¦ä¸ï¼
解ï¼åCEçä¸ç¹ä¸ºGï¼è¿æ¥DG设CG=aï¼åEG=aï¼AE=4aâµDæ¯BCä¸ç¹â´DGæ¯â³BCEçä¸ä½çº¿â´DGâBEâ´AF:FD=AE:EG=4:1åçå¯å¾ï¼EF=4DG/5BE=2DGBE:FE=2:(4/5)=5:2BF:FE=(5:2)-1=3:2