证明:
不等式是关于a、b、c的对称,不妨设a>=a>=b>=c,
则a-b、b-c、a-c都为正实数,
且a/b>=1,b/c>=1,c/a>=1
故(a^a*b^b*c^c)/(abc)^[(a+b+c)/3]
=a^[(2a-b-c)/3]*b^[(2b-a-c)/3]*c^[(2c-a-b)/3]
=a^[(a-b)/3]*a^[(a-c)/3]*b^[(b-a)/3]*b^[(b-c)/3]*c^[(c-a)/3]*c^[(c-b)/3]
=(a/b)^[(a-b)/3]*(b/c)[(b-c)/3]*(a/c)^[(a-c)/3]
>=1
故a^a*b^b*c^c>=(abc)^[(a+b+c)/3].
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