C语言编程如何判断输入整数的正负性和奇偶性？

Question

如题所述

Answer 1

void main()
{
int num;
scanf("%d",&num);
if(num>0)
{printf("该数是正数\n;}
else
{printf("该数是负数\n;}
num=num%2;
if(num==0)
{prin订鸡斥课俪酒筹旬船莫tf("该数是偶数\n;}
else
{printf("该数是奇数\n;}

#include<stdio.h>
main()
{
int x,y;
printf("Please input a integer:");      /*输入一个整数！*/
scanf("%d",x);
if(x<0)
printf("It's a negative number!");  /*输入的数是负数！*/
else
printf("It's a positive number!");  /*输入的数是正数！*/
y=x%2;
if(0==y)
printf("It's a even number!");      /*输入的数是偶数！*/
else
printf("It's a odd number!");       /*输入的数是奇数！*/
}

右边的是注释！

Answer 2

#include<stdio.h>
main()
{
int
x,y;
printf("Please
input
a
integer:");
/*输入一个整数！*/
scanf("%d",x);
if(x<0)
printf("It's
a
negative
number!");
/*输入的数是负数！*/
else
printf("It's
a
positive
number!");
/*输入的数是正数！*/
y=x%2;
if(0==y)
printf("It's
a
even
number!");
/*输入的数是偶数！*/
else
printf("It's
a
odd
number!");
/*输入的数是奇数！*/
}
右边的是注释！