出20道有理数的加减法,附答案,但不要过程

如题。
可以给100

①-7/5 +(+ 1/10) 
=-1.3 
     
②90-(-3)
=93

③-0.5-(-3 )+2.75-(+7 )
=-0.75

④ (-2.8)+(+1.9)
=-0.9

1)(-9)-(-13)+(-20)+(-2)
=-18

(2) 3+13-(-7)÷6
=17又6分之1

(3) (-2)-8-14-13
=-37

(4) (-7)×(-1) ÷7+8
=9

(5) (-11)×4-(-18) ÷18
=-43

(-38)+52+118+(-62)
=70

(-32)+68+(-29)+(-68)
=-61

(-21)+251+21+(-151)
=0

12+35+(-23)+0
=14

(-6)+8+(-4)+12
=10

27+(-26)+33+(-27)
=7

39+[-23]+0+[-16]
=0

[-18]+29+[-52]+60
=153

[-3]+[-2]+[-1]+0+1+2
=9

(-301)+125+301+(-75)
=50

11/12-10/12= -1/12
=36

1/3- 7/12-7/18
=-23/36

1 -1/3-1 1/5
=7/15

10-7/10= 9又3/10
5/24+3/8
=7/8

4.39x1/13x2/3
=2

1+(-2)+(-3)+4+5+(-6)+(-7)+8+9+(-10)+(-11)+12
=0

(-7分之1)+(-7分之2)+1又7分之3
=1
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第1个回答  2016-03-23
①-7/5 +(+ 1/10) 
=-1.3 
     
②90-(-3)
=93
③-0.5-(-3 )+2.75-(+7 )
=-0.75
④ (-2.8)+(+1.9)
=-0.9
1)(-9)-(-13)+(-20)+(-2)
=-18
(2) 3+13-(-7)÷6
=17又6分之1
(3) (-2)-8-14-13
=-37
(4) (-7)×(-1) ÷7+8
=9
(5) (-11)×4-(-18) ÷18
=-43
(-38)+52+118+(-62)
=70
(-32)+68+(-29)+(-68)
=-61
(-21)+251+21+(-151)
=0
12+35+(-23)+0
=14
(-6)+8+(-4)+12
=10
27+(-26)+33+(-27)
=7
39+[-23]+0+[-16]
=0
[-18]+29+[-52]+60
=153
[-3]+[-2]+[-1]+0+1+2
=9
(-301)+125+301+(-75)
=50
11/12-10/12= -1/12
=36
1/3- 7/12-7/18
=-23/36

1 -1/3-1 1/5
=7/15

10-7/10= 9又3/10
5/24+3/8
=7/8
4.39x1/13x2/3
=2
1+(-2)+(-3)+4+5+(-6)+(-7)+8+9+(-10)+(-11)+12
=0
(-7分之1)+(-7分之2)+1又7分之3
=1
第2个回答  2018-09-16
6666666对了!!!
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