因式分解(x-y)^2-(y-x)应为什么?要过程

如题所述

(x-y)^2-(y-x)
=(x-y)^2-[-(x-y)]
=(x-y)^2+(x-y)
=(x-y)(x-y+1)
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第1个回答  2009-10-09
(x-y)(x-y)+(x-y)
(x-y)(x-y+1)
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