1.使ç¨Character.isDigit(char)å¤æ
char num[] = str.toCharArray();//æå符串转æ¢ä¸ºå符æ°ç»
StringBuffer title = new StringBuffer();//使ç¨StringBufferç±»ï¼æéæ°åæ¾å°titleä¸
StringBuffer hire = new StringBuffer();//ææ°åæ¾å°hireä¸
for (int i = 0; i < num.length; i++) {
// å¤æè¾å
¥çæ°åæ¯å¦ä¸ºæ°åè¿æ¯å符
if (Character.isDigit(num[i])) {æå符串转æ¢ä¸ºå符ï¼åè°ç¨Character.isDigit(char)æ¹æ³å¤ææ¯å¦æ¯æ°åï¼æ¯è¿åTrueï¼å¦åFalse
hire.append(num[i]);// å¦æè¾å
¥çæ¯æ°åï¼æå®èµç»hire} else {title.append(num[i]);// å¦æè¾å
¥çæ¯å符ï¼æå®èµç»title}}}
2.使ç¨ç±»å转æ¢å¤ætry {String str="123abc";
int num=Integer.valueOf(str);//æå符串强å¶è½¬æ¢ä¸ºæ°å
return true;//å¦ææ¯æ°åï¼è¿åTrue
} catch (Exception e) {
return false;//å¦ææåºå¼å¸¸ï¼è¿åFalse}
3.使ç¨æ£å表达å¼å¤æ
String str = "";
boolean isNum = str.matches("[0-9]+");
//+表示1个æå¤ä¸ªï¼å¦"3"æ"225"ï¼ï¼*表示0个æå¤ä¸ªï¼[0-9]*ï¼ï¼å¦""æ"1"æ"22"ï¼ï¼?表示0个æ1个([0-9]?)(å¦""æ"7")
psï¼è¿ä¸ªæ¹æ³åªè½ç¨äºå¤ææ¯å¦æ¯æ£æ´æ°
温馨提示:答案为网友推荐,仅供参考