第1个回答 2013-11-19
#include <stdio.h>
int a[300],cnt=0;
double pjz1=0.0,pjz2=0.0;
jsValue()
{
int i,n=0,sum1=0,sum2=0;
for(i=0;i<300;i++)
{
if((a[i]/1000 - (a[i]%1000)/100 - (a[i]%100)/10 -a[i]%10)>0)
{sum1+=a[i];cnt++;}
else {sum2+=a[i];n++;}
}
pjz1=(double)sum1/cnt;
pjz2=(double)sum2/n;
}
main()
{
int i;
readDat();
jsValue();
writeDat();
printf("cnt=%d\n满足条件的平均值pzj1=%7.21f\n不满足条件的平均值pzj2=%7.21f\n",
cnt,pjz1,pjz2);
}
readDat()
{
FILE *fp;
int i;
fp=fopen("IN15.DAT","r");
for (i=0;i<300;i++) fscanf(fp, "%d,",&a[i]);
fclose(fp);
}
writeDat()
{
FILE *fp;
int i;
fp=fopen("OUT15.DAT","w");
fprintf(fp,"%d\n%7.21f\n%7.21f\n",cnt,pjz1,pjz2);
fclose(fp);
}