求一个在VC6.0上运行C语言程序

Question

运行该程序能显示出500～1000之间所有素数（质数），且每显示6个就换一行

Answer 1

函数说明：
素数定义：能被自身和1整除的数
500到1000中的素数从501开始的所以 初始值A=501 终值C=1000
计算值B=502 这里有一个关系：A/B是否等于零
可以随便定义 起始值和终值
如果定义500开始则为计算500到1000中的偶数

#include <stdio.h>
main ()
{
int A,B,C;
int i,j,k=0;
printf("\n 起始值A=");
scanf("%d",&A);
printf("\n 终值C=");
scanf("%d",&C);
printf("\n 素数计算值B=");
scanf("%d",&B);
for (i=A;;i+=2) //顺次把i加1
{
for(j=B;j<=i;j++) //素数的判定
if(i%j==0)
break;
if(j>=i)
{
printf("%6d",i); //输出值之间的间隔
k++;
if(k%6==0) //按一排6个输出
printf("\n");
}
if(i<C)
continue; //判断是否到1000了
else break;
}

}

Answer 2

2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,
53,59,61,67,71,73,79,83,89,97,
101,103,107,109,113,127,131,137,139,149,
151,157,163,167,173,179,181,191,193,197,199,
211,223,227,229,233,239,241,
251,257,263,269,271,277,281,283,293,
307,311,313,317,331,337,347,349,
353,359,367,373,379,383,389,397,
401,409,419,421,431,433,439,443,449,
457,461,463,467,479,487,491,499,
503,509,521,523,541,547,
557,563,569,571,577,587,593,599,
601,607,613,617,619,631,641,643,647,
653,659,661,673,677,683,691,
701,709,719,727,733,739,743,
751,757,761,769,773,787,797,
809,811,821,823,827,829,839,
853,857,859,863,877,881,883,887,
907,911,919,929,937,941,947,
953,967,971,977,983,991,997

[总共168个]