这题跪求各位数学学霸解答一下了,实在不会,急急急

如题所述

(1)因为∠A =70°
所以∠ABC+∠ACB=110°
∠p=180°-1/2 (∠ABC+∠ACB)=125°
(2)因为∠A =70°
所以∠ABC+∠ACB=110°
∠p=180°-{1/2(180°- ∠ABC)+1/2(180°-∠ACB)}
=180°-(90°-1/2 ∠ABC+90°-∠1/2ACB)
=180°-90°+1/2 ∠ABC-90°+∠1/2ACB)
=1/2(∠ABC+∠ACB)
=55°追问

第三题呢

还有两小题

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