1.如图,在正方形ABCD中,对角线AC,BD交于点O,E是CD边上一点,AE与BD交于点M,连接CM。点F是CB边上一点,AF交DB于点N,连接CN。(1)若角CME=30度,角CNF=50度,求角EAF的度数。这里是图片地址:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/fcfaaf51f3deb48f2fe27bfaf01f3a292df5780f?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
2.如图,直角梯形ABCD中,AD\\BC,角ADC=90度,L是AD的垂直平分线,交AD于点M,以腰AB为边作正方形ABFE,作EP垂直L于P,求证:2EP+AD=2CD这里是图片地址:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/9213b07eca80653875007e3797dda144ad348228?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
1.三角形的一个外角等于与其不相邻的两个内角之和可以证∴△ADM≌△CMD所以MAO=MCO因为外角=30.所以角MAO=15可以证∴△ANB≌△CNB同理角OAN=25所以……角EAF=40 2.过点A做AQ垂直于BC,过点E做EO垂直于AD证AQB全等于AEO2EP+AD=2CD 可以转换成2EP+2AM=2AQ因为AQB全等于AEO所以AO=AQ 即AM+MO=AQ即AM+EP=AQ剩下得应该会了