第2个回答 2020-09-29
|-5p/(100-5p)|>1
可以分成两个不带绝对值的不等式来解:
(1)-5p/(100-5p)>1
-p/(20-p)>1
-p/(20-p)-1>0
p/(20-p)+1<0
p/(20-p)+(20-p)/(20-p)<0
(p+20-p)/(20-p)<0
20/(20-p)<0
20-p<0
p>20
(2)-5p/(100-5p)<-1
-p/(20-p)<-1
-p/(20-p)+1<0
p/(20-p)-1>0
p/(20-p)-(20-p)/(20-p)>0
(p-20+p)/(20-p)>0
(2p-20)/(20-p)>0
(p-10)/(20-p)>0
10<10<20或
p>20
p<20