解ï¼
2ãlog4 (16)=2
=(lg4/lg3)Ãï¼lg8/lg4)Ã(lgm/lg8)
=(lg8/lg3)Ã(lgm/lg8)
=lgm/lg3
å lgm=2lg3=lg9
æ
m=9
3ã(1)åå¼=5÷[5^(log0.2 <3>)]
=5÷[5^(-log5 <3>)]
=5÷(1/3)
=15
(2)åå¼=(lg16/lg27)÷(lg4/lg3)
=(4lg2/3lg3)÷(2lg2/lg3)
=(4/3)Ã(1/2)
=2/3
(3)åå¼=lg243/lg9
=lg(3^5)/2lg3
=5/2
(4)åå¼=(1/2)(lg3/lg4)+3Ã(1/4)-(1/2)(lg6/lg4)
=(1/2)(lg3/lg4)-(1/2)(lg6/lg4)+(3/4)
=(1/2)(lg3-lg6)/lg4 +(3/4)
=(1/2)lg(1/2)/lg4 +(3/4)
=(1/2)Ã(-1/2)+(3/4)
=1/2
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