第1个回答 2020-06-16
int main()
{
int a[10] = { 1,2,3,4,5,6,7,8,9,10 };
for (int i = 0; i < 10; i++)
{
printf("%d\t",a[i]);
}
printf("\n");
int* p = a;
int n = 0;
while (n<10)
{
if (*p % 2 == 1)
{
printf("%d\t", n);
}
else
printf("\t");
p++;
n++;
}
}本回答被网友采纳