(1)
2(x-1)²=x²-1
解:2【x²-2x+1】=x²-1
2x²-4x+2=x²-1
2x²-4x+2+1-x²=0
x²-4x+3=0
(x-1)(x-3)=0
x₁=1
x₂=3
(2)
(y+3)²/8-y=(y+3) /4-(y-1)/2
解:y²+6y+9-8y=2(y+3)-4(y-1)--------各项分别乘8
y²+6y+9-8y=2y+6-4y+4 ----------去括号
y²+6y-8y-2y+4y=6+4-9 ---------------移项
y²=1
y¹=-1
y₂=1
望采纳、、
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