求帮忙把以下几个数学公式写出具体计算步骤

Question

求解（a-1/2）^2（a^2+1/4）^2(a+1/2)^2=a^8-1/8a^4+1/256
(-3/4X^6Y^3+6/5X^3Y^4-9/10XY^5)除以3/5XY^3=-5/4X^5+2X^2Y-3/2Y^2
X^M- 1/2X^m+1 - 1/5X^m + X^m+1 - 2X^m+1 = 4/5X^m- 3/2X^m+1
求着几道题的具体步骤~~~我发现现在这辅导书真精简啊~~

Answer 1

1、利用平方差公式，完全平方式展开
（a-1/2）^2（a^2+1/4）^2(a+1/2)^2=（a-1/2）^2 * (a+1/2)^2 *（a^2+1/4）^2
=（a^2-1/4）^2 *（a^2+1/4）^2 平方差公式
=（a^4 -1/16）^2 平方差公式
=a^8-1/8a^4+1/256 完全平方式展开
2、利用 a^m/a^n =a^(n-m),将式子拆开来算，就是结果
(-3/4X^6Y^3+6/5X^3Y^4-9/10XY^5)/ [3/5XY^3 ]
=[-3/4X^6Y^3)] / [3/5XY^3 ] +[6/5X^3Y^4] / [3/5XY^3 ] - [9/10XY^5)] / [3/5XY^3 ]
=...
3、合并同类项
X^M- 1/2X^m+1 - 1/5X^m + X^m+1 - 2X^m+1
= X^M - 1/5X^m - 1/2X^m+1 + X^m+1 - 2X^m+1
=（1-1/5)X^M +(-1/2 + 1-2)X^(M+1)
=4/5X^m- 3/2X^(m+1)

Answer 2

题目看不懂，能打的清楚点吗 你照片拍下来好了，用摄像头就行

Answer 3

1、
（a-1/2）^2（a^2+1/4）^2(a+1/2)^2=（a-1/2）^2 * (a+1/2)^2 *（a^2+1/4）^2
=（a^2-1/4）^2 *（a^2+1/4）^2
=（a^4 -1/16）^2
=a^8-1/8a^4+1/256
2、
(-3/4X^6Y^3+6/5X^3Y^4-9/10XY^5)/ [3/5XY^3 ]
=[-3/4X^6Y^3)] / [3/5XY^3 ] +[6/5X^3Y^4] / [3/5XY^3 ] - [9/10XY^5)] / [3/5XY^3 ]
=...
3、
X^M- 1/2X^m+1 - 1/5X^m + X^m+1 - 2X^m+1
= X^M - 1/5X^m - 1/2X^m+1 + X^m+1 - 2X^m+1
=（1-1/5)X^M +(-1/2 + 1-2)X^(M+1)
=4/5X^m- 3/2X^(m+1)