有机物A的相对分子质量为44,能与银氨溶液反应,含有-CHO,可推知A为CH
3CHO,A系列反应得到C,M再浓硫酸条件反应得到C与D,应是发生酯的水解反应,故B为CH
3CHOONH
4,C为CH
3COOH,故D的化学式为C
7H
6OBr
2,E与氢氧化铜浊液反应生成砖红色沉淀与F,说明E中含有-CHO,G遇氯化铁溶液显色,G中含有酚羟基-OH,H转化为I时,产物只有一种结构,说明D、E、F、H、I中苯环上的取代基处于对位,由M在浓硫酸、加热条件下生成乙酸与D,结合信息可知,D应为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/4ec2d5628535e5dde3f5116e75c6a7efcf1b62a1?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,M为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/14ce36d3d539b600ed11bb06ea50352ac75cb7a0?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,则E为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/63d0f703918fa0eca301d0bc259759ee3c6ddbb9?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,根据有机物的转化可知F为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/241f95cad1c8a786ffebfebf6409c93d71cf50b9?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,G为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/94cad1c8a786c91748dae688ca3d70cf3ac757a1?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,H为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/f7246b600c3387442d049bcd520fd9f9d62aa0ba?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,则I为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/1b4c510fd9f9d72aaba5a4acd72a2834359bbbba?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,
(1)G→H是
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/94cad1c8a786c91748dae688ca3d70cf3ac757a1?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
与氢气发生加成反应生成
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/f7246b600c3387442d049bcd520fd9f9d62aa0ba?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,
故答案为:加成反应;
(2)H为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/f7246b600c3387442d049bcd520fd9f9d62aa0ba?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,含有的官能团为:羟基、羧基,D的结构简式为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/4ec2d5628535e5dde3f5116e75c6a7efcf1b62a1?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,
故答案为:羟基、羧基;
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/4ec2d5628535e5dde3f5116e75c6a7efcf1b62a1?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
;
(3)))①A→B是乙醛被银氨溶液氧化,反应方程式为:CH
3CHO+2Ag(NH
3)
2OH
2Ag↓+CH
3COONH
4+3NH
3+H
2O,
②H为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/f7246b600c3387442d049bcd520fd9f9d62aa0ba?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,通过消去反应可生成
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/1b4c510fd9f9d72aaba5a4acd72a2834359bbbba?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,反应的方程式为:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/adaf2edda3cc7cd978ec80683a01213fb90e91ba?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,
故答案为:CH
3CHO+2Ag(NH
3)
2OH
2Ag↓+CH
3COONH
4+3NH
3+H
2O;
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/adaf2edda3cc7cd978ec80683a01213fb90e91ba?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
;
(4)与
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/94cad1c8a786c91748dae688ca3d70cf3ac757a1?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
互为同分异构体,苯环上有两个取代基,且遇FeCl
3溶液显色,则含有酚羟基,另外取代基为-COOH,有邻、间两种位置,也可以为-OOCH,与羟基有邻、间、对三种位置,故符合条件的同分异构体共有5种,
故答案为:5.