线性代数基础，伴随矩阵与逆矩阵问题

Question

如题所述

Answer 1

|(4A)^(-1)+3A*| = |(1/4)A^(-1)+3|A|A^(-1)| = |(1/4)A^(-1) - A^(-1)|
= |(-3/4)A^(-1)| = (-3/4)^3/|A| = (-27/64)/(-1/3) = 81/64本回答被提问者采纳