æ±è¿ ç¹ï¼2,0ï¼çä¸æ¡ç´çº¿ï¼ä½¿å®ä¸æ²çº¿y=1/xç¸åã
解ï¼ç¹A(2ï¼0)æ¯æ²çº¿y=1/xçç¹ï¼å¯ç¨ä»¥ä¸æ¹æ³æ±è§£ï¼
yâ²=-1/x²ï¼è®¾è¿ç¹A(2ï¼0)çå线ä¸æ²çº¿y=1/xç¸åäºB(mï¼n)ï¼åæ以ä¸çå¼ï¼
KAB=n/(m-2)=-1/m²............(1)
n=1/m................................(2)
å°(2)代å
¥(1)å¼å¾ 1/[m(m-2)]=-1/m²ï¼å³æ1/(m-2)=-1/mï¼m-2=-mï¼2m=2ï¼æ
m=1ï¼n=1ï¼
å³åç¹Bçåæ 为(1ï¼1)ï¼æ
KAB=-1ï¼å线æ¹ç¨ä¸º y=-(x-2)=-x+2.
温馨提示:答案为网友推荐,仅供参考