(1+1/2+1/3+1/4)×(1/2+1/3+1/4+1/5)-(1+1/2+1/3+1/4+1/5)×(1/2+1/3+1/4)

如题所述

(1+1/2+1/3+1/4)=a,(1/2+1/3+1/4+1/5)=b
原式=ab-(a+1/5)*(b-1/5)
=ab-(ab+1/5b-1/5a-1/25)
=ab-ab-1/5b+1/5a+1/25
=1/5(a-b)+1/25
=1/5*4/5+1/25
=4/25+1/25
=1/5
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第1个回答  2012-04-23
1/2+1/3+1/4=A,1/2+1/3+1/4+1/5=B
原式=(1+A)×B-(1+B)×A
=B+AB-A-AB
=B-A
=(1/2+1/3+1/4+1/5)-(1/2+1/3+1/4)
=1/5
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